Files
Dhruv Manilawala 22177e6915 [ty] Surface matched overload diagnostic directly (#18452)
## Summary

This PR resolves the way diagnostics are reported for an invalid call to
an overloaded function.

If any of the steps in the overload call evaluation algorithm yields a
matching overload but it's type checking that failed, the
`no-matching-overload` diagnostic is incorrect because there is a
matching overload, it's the arguments passed that are invalid as per the
signature. So, this PR improves that by surfacing the diagnostics on the
matching overload directly.

It also provides additional context, specifically the matching overload
where this error occurred and other non-matching overloads. Consider the
following example:

```py
from typing import overload


@overload
def f() -> None: ...
@overload
def f(x: int) -> int: ...
@overload
def f(x: int, y: int) -> int: ...
def f(x: int | None = None, y: int | None = None) -> int | None:
    return None


f("a")
```

We get:

<img width="857" alt="Screenshot 2025-06-18 at 11 07 10"
src="https://github.com/user-attachments/assets/8dbcaf13-2a74-4661-aa94-1225c9402ea6"
/>


## Test Plan

Update test cases, resolve existing todos and validate the updated
snapshots.
2025-06-20 08:36:49 +05:30

3.3 KiB

Calling a union of function types

[environment]
python-version = "3.12"

A smaller scale example

def f1() -> int:
    return 0

def f2(name: str) -> int:
    return 0

def _(flag: bool):
    if flag:
        f = f1
    else:
        f = f2
    # error: [too-many-positional-arguments]
    # error: [invalid-argument-type]
    x = f(3)

Multiple variants but only one is invalid

This test in particular demonstrates some of the smarts of this diagnostic. Namely, since only one variant is invalid, additional context specific to that variant is added to the diagnostic output. (If more than one variant is invalid, then this additional context is elided to avoid overwhelming the end user.)

def f1(a: int) -> int:
    return 0

def f2(name: str) -> int:
    return 0

def _(flag: bool):
    if flag:
        f = f1
    else:
        f = f2
    # error: [invalid-argument-type]
    x = f(3)

Try to cover all possible reasons

These tests is likely to become stale over time, but this was added when the union-specific diagnostic was initially created. In each test, we try to cover as much as we can. This is mostly just ensuring that we get test coverage for each of the possible diagnostic messages.

from inspect import getattr_static
from typing import overload

def f1() -> int:
    return 0

def f2(name: str) -> int:
    return 0

def f3(a: int, b: int) -> int:
    return 0

def f4[T: str](x: T) -> int:
    return 0

@overload
def f5() -> None: ...
@overload
def f5(x: str) -> str: ...
def f5(x: str | None = None) -> str | None:
    return x

@overload
def f6() -> None: ...
@overload
def f6(x: str, y: str) -> str: ...
def f6(x: str | None = None, y: str | None = None) -> str | None:
    return x + y if x and y else None

def _(n: int):
    class PossiblyNotCallable:
        if n == 0:
            def __call__(self) -> int:
                return 0

    if n == 0:
        f = f1
    elif n == 1:
        f = f2
    elif n == 2:
        f = f3
    elif n == 3:
        f = f4
    elif n == 4:
        f = 5
    elif n == 5:
        f = f5
    elif n == 6:
        f = f6
    else:
        f = PossiblyNotCallable()
    # error: [too-many-positional-arguments]
    # error: [invalid-argument-type] "Argument to function `f2` is incorrect: Expected `str`, found `Literal[3]`"
    # error: [missing-argument]
    # error: [invalid-argument-type] "Argument to function `f4` is incorrect: Argument type `Literal[3]` does not satisfy upper bound of type variable `T`"
    # error: [invalid-argument-type] "Argument to function `f5` is incorrect: Expected `str`, found `Literal[3]`"
    # error: [no-matching-overload] "No overload of function `f6` matches arguments"
    # error: [call-non-callable] "Object of type `Literal[5]` is not callable"
    # error: [call-non-callable] "Object of type `PossiblyNotCallable` is not callable (possibly unbound `__call__` method)"
    x = f(3)
def any(*args, **kwargs) -> int:
    return 0

def f1(name: str) -> int:
    return 0

def _(n: int):
    if n == 0:
        f = f1
    else:
        f = any
    # error: [parameter-already-assigned]
    # error: [unknown-argument]
    y = f("foo", name="bar", unknown="quux")