mirror of https://github.com/astral-sh/ruff
508c0a0861
In the following example, there are two occurrences of `typing.Self`,
one for `Foo.foo` and one for `Bar.bar`:
```py
from typing import Self, reveal_type
class Foo[T]:
def foo(self: Self) -> T:
raise NotImplementedError
class Bar:
def bar(self: Self, x: Foo[Self]):
# SHOULD BE: bound method Foo[Self@bar].foo() -> Self@bar
# revealed: bound method Foo[Self@bar].foo() -> Foo[Self@bar]
reveal_type(x.foo)
def f[U: Bar](x: Foo[U]):
# revealed: bound method Foo[U@f].foo() -> U@f
reveal_type(x.foo)
```
When accessing a bound method, we replace any occurrences of `Self` with
the bound `self` type.
We were doing this correctly for the second reveal. We would first apply
the specialization, getting `(self: Self@foo) -> U@F` as the signature
of `x.foo`. We would then bind the `self` parameter, substituting
`Self@foo` with `Foo[U@F]` as part of that. The return type was already
specialized to `U@F`, so that substitution had no further affect on the
type that we revealed.
In the first reveal, we would follow the same process, but we confused
the two occurrences of `Self`. We would first apply the specialization,
getting `(self: Self@foo) -> Self@bar` as the method signature. We would
then try to bind the `self` parameter, substituting `Self@foo` with
`Foo[Self@bar]`. However, because we didn't distinguish the two separate
`Self`s, and applied the substitution to the return type as well as to
the `self` parameter.
The fix is to track which particular `Self` we're trying to substitute
when applying the type mapping.
Fixes https://github.com/astral-sh/ty/issues/1713
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